Collisions

media type="youtube" key="HfvbOGWjNUE" height="364" width="445" This page is about Collisions and what we can do to prevent them. We have done research, an example scenario, it calculations and ways to avoid the problem. Most collisions happen when one or two drivers are preoccupied and not paying attention on the road. Other collisions occur in situations when debris falls off cars and the cause of the would be cars be hind it to spin out. There are situation many situation regarding collisions and the question is, what can we do about it? Research showed that there are 6 million care accidents in the US every year. The affects of them result in about 3 million injuries and 2 million that are permanent. In Pennsylvania alone there are 2.5 million rear-end collisions a year.
 * __What's this about?:__**
 * __Research:__**

**__Scenario:__** **Harrison is driving down a small two way street coming from Block Busters in Winfield. The street is a total of 600 feet.He has traveled down the road many times and has always been the only driver on the road. He starts at the beginning of the street (origin) and is going at a constant speed of 11.17m/s and is busy changing the stations on his radio. Another car starts at the end of street, is accelerating in a negative direction at 6.7m/s every 3s. Harrison didn't realize that he drifted on the same side of the road as the other driver. At what point would the two cars collide.**

Car A=11.17 m/s- constant velocity Car B=6.7 m/s every 3 seconds To find the velocity per second of car B, you divide the the velocity (6.7 m/s) by 3 seconds. Since you are given that is the velocity every 3 seconds if you divide by 3 you can find the velocity per one second. -2.333m/s every 1 second To make sure the height of the bridge is in meters. You have to find how many meters are in a foot. -Every foot->meter is 1ft=0.3048m->approximately .30m Now that we know the ratio we can simply multiply the amount of feet by how many feet go into 1 meter. 600ft*.30m=180m Now you can make 2 equations one for car a and another for car b. This way you can make a position vs time map. So this way you can see the point of collisions by way the two lines meet. Another way to find a solution to the problem is by using system of equations. Since you already have two equations one for each car you can use them to solve for the x, which is the velocity, and the y which is the starting point. Car A-11.17x Car B-18-2.3333x 11.17x=18-2.333x 13.50x=18 x=1.33333
 * __The Calculations;__**

Then once you find your x you can plug it in to either question 11.17(1.3333)=14.89 y=14.89 If you round your x and y to the nearest whole number it will give you the same answer as the graph. **At what point would the two cars collide?** (1,15) To Avoid this problem, Harrison would have to pay closer attention to the road and focus on his radio at a time that is appropriate, for example a red light. For the other driver, if their car continues to shut off, they should pull over to the other side of the road so that they could be a a less risk of collision.
 * __Avoid the Problem:__**

[|Traffic Collisions] [|Collisions Statistics] This relates to Kinematics, because knowing the time, displacement, acceleration, velocity, and the position of an object, you can determine when certain situations are going to happen. This relates to Kinematics, because if the driver knew the displacement and the time the about of time it would take for the collision for occur, he could have easily avoided the situation.
 * Statistics or News Articles Related to this Hazard (yes, the statistics and articles must be real and cited!)**
 * How the Kinematics Relate to This Hazard**
 * How this Hazard Can Be Avoided With a Better Knowledge of Kinematics**